Please Help - Account Not Authorized Error

[NITIN PANDE]

The trust account is machine specific.  Since you added the machine account
manually in your smb.conf, it (probably) is causing problems in the new
box.  I would suggest you rid the manual part and add the trust account
using this:
smbpasswd -a -m <machine_name>
HTH,
Ciao,
Nitin Pande
Mail Administrator

WebGuardian wrote:

> Hello,
>
> We have a situation here that we sure could use some help on. Let me
> explain what we did so far:
>
> On a test Red Hat 7.1 box we installed Samba 2.2.1a. From there we
> created the below smb.conf file and manually added the machine account
> to the system and then added it to the smbpasswd file. We then added the
> root account to the smbpasswd file.
>
> Then we proceeded to join the MAINOFFICE domain with our Windows 2000sp2
> test client, and to our surprise it worked flawlessly. We then added
> users to the smbpasswd file and we could then log in from the W2K box.
> Not so much as a hiccup.
>
> Since we experienced positive results with that, we unjoined the domain
> with our W2K client and then removed samba from our
> test box. We then installed Samba on one of production servers that we
> had slated for this role. We then followed the procedures
> from above and loaded the same exact smb.conf file we used before and
> started the services.
>
> This time we got a whole new ballgame. When we attempt to join the
> domain from our test W2k client we get an error message
> "The account is not authorized to login from this station"
>
> Anyone have any ideas?
>
> Thanks in advance
>
> Bruce P. Morin
>
>
> [global]
> security = user
> status = yes
> workgroup = MAINOFFICE
> encrypt passwords = yes
> domain logons =yes
> logon script = scripts\%U.bat
> domain admin group = @adm
> guest account = ftp
> share modes= no
> os level=65
>
> [homes]
> guest ok = no
> read only = no
> create mask = 0700
> directory mask = 0700
> oplocks = false
> locking = no
> [netlogon]
>
> path = /usr/local/samba/netlogon
> writeable = no
> guest ok = no