[Samba] Bug in Samba v2.2.8a with Windows API GetFileAttributes ?

Bill Smith bsmith at odi.com
Thu Apr 10 21:59:52 GMT 2003

Before my company was bought out by another company, we were using Samba
v1.9.3 and I'm pretty certain that the GetFileAttributes was working
properly but I can't be absolutely sure. Since the move, we're using v2.2.5
and just recently upgraded to v2.2.8a on Solaris 2.7.  I'm doing my testing
on an XP machine.

I'm seeing that GetFileAttributes is always returning 0 instead of a hex
value for any valid file pathname accessed via the samba server.  If I
access the same file locally or via another NT server, I get valid results:

Accessign a file locally:

D:\temp>test d:\temp\wyb.zip
 SUCCESS: pathname [d:\temp\wyb.zip] is a file! rc=2820

Accessing a file on an NT server:

D:\temp>test \\absolut\home\b\bsmith\xmas01.xls
 SUCCESS: pathname [\\absolut\home\b\bsmith\xmas01.xls] is a file! rc=20

Accessing a file via a solaris samba server

D:\temp>test \\crystal\h\crystal\16\du-crystal16
 FAILURE: pathname [\\crystal\h\crystal\16\du-crystal16] is not a file! rc=0

D:\temp>ls -al \\crystal\h\crystal\16\du-crystal16
-rwxrwxrwx   1 CRYSTAL\root    CRYSTAL\other    991546 Apr 10 02:34

Here the test program that I used with VC++ 6.0:

#include <windows.h>
#include <iostream.h>

int main (int argc, char** argv) {

  if (argc != 2) {
    cout << "Usage: test <pathname>" << endl;
    return 1;

  const char* pn = argv[1];

  DWORD rc = GetFileAttributes(pn);
  if (0xFFFFFFFF != rc &&
      (rc &
      cout << " SUCCESS: pathname [" << pn << "] is a file! rc=" << hex <<
rc << endl;
      return 0;
  else {
    cout << " FAILURE: pathname [" << pn << "] is not a file! rc=" << hex <<
rc << endl;
    return 1;

Thanks in advance for any advice or suggestions.

--Bill Smith

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