[clug] Substring repetition detection
Martin Pool
mbp at samba.org
Wed Jun 25 17:08:19 EST 2003
On 25 Jun 2003, Michael Still <mikal at stillhq.com> wrote:
> Anyways, I can't think of a good answer. Any hints?
Brute force and ignorance. :-)
Consider all n-character substrings (n>=2) starting at position m
(m>=0). Is that equal to the substring starting at m+n? If so, what
about m+2n, etc. Then recursively check for more repeated strings
later on.
Repeat for all n, m, and keep the best solution.
--
Martin
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