[Samba] permissions question
Nicolas Jungers
nicolas at jungers.net
Wed Sep 1 08:49:28 MDT 2010
On 2010-09-01 15:00, alexr wrote:
> On Tue Aug 31 2010 23:02:26 GMT+0200 Nicolas Jungers
> <nicolas at jungers.net> wrote:
>>
>> a mask is a "removal" of bit in the permission, so you get that a bit
>> wrong :-)
>>
>> say you have permissions of 777 which in binary is 111-111-111 and a
>> mask of 022 which is 000-010-010 you have to do the following to get the
>> final permissions:
>> 111-111-111
>> - 000-010-010
>> = 111-101-101
>>
>> which is 755
>>
>> N.
>>
>
> According to the manual your example is not right. The "create mask"
> will be logically ANDed with the current/default permissions and the
> "force create mode" will be ORed. For your example that means:
>
> 111-111-111
> AND 000-010-010
> = 000-010-010
>
> It is right that the "create mask" removes bits, but not the way you
> showed it. The manual says about "create mask":
> "Any bit not set here will be removed from the modes set on a file when
> it is created."
>
> Because the "force create mode" will be ORed, it adds bits. These bits
> are guaranteed to be set on the file. Extended example with "force
> create mode" of 110-100-100:
>
> 111-111-111
> AND 000-010-010 (create mask)
> = 000-010-010
> OR 110-100-100 (force create mode)
> = 110-110-110
You're right. I've confused create mask and umask.
N.
More information about the samba
mailing list