sizeof() on constant strings

[Stefan (metze) Metzmacher]

Am 02.09.2014 um 07:18 schrieb Andrew Bartlett:
> Just a hint I found out the hard way recently:
> 
> char *foo = "ba";
> and 
> char foo[] = "ba";
> give different results when you do sizeof(foo).  See attached test
> program. 

And having char f3[5] as a function argument is different too.

$ ./test
sizeof(char) = 1
sizeof(char *) = 8
sizeof(const char *f2 = "food") = 8
sizeof(const char f3[] = "food") = 5
func sizeof(char) = 1
func sizeof(char *) = 8
func sizeof(const char *f2 = "food") = 8
func sizeof(const char f3[] = "food") = 8

metze
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