Kevin Pulo wrote on 22/03/10 9:34 PM:
>
> Or O(n), considering there's a fork in the loop.
>
> Have I missed something? What's wrong with the ultra-simple:
>
> n=5; s=""; while [ ${#s} -lt $n ]; do s="$s*"; echo "$s"; done
>
> ???
Better again. Thanks!
In bash [[ ]] doesn't fork.
>
> Kev.