[clug] More info, please - was Re: Tridge's coffee contraption - photos
paulus at samba.org
Tue Dec 1 04:19:53 MST 2009
Alastair D'Silva writes:
> Theres a good example on AVR's site:
> The example is for a mains coupled microcontroller (likely powered by a
> capacitive supply from the mains) - since we want isolation, I would add an
> optocoupler, and clamping diodes (the example uses the internal diodes of
> the microcontroller).
So, 1Mohm resistor from active to the photodiode anode, neutral to the
photodiode cathode, with a diode across the photodiode - is that the
I'm afraid that won't work very well at all. The current through the
photodiode will rise gradually from 0 to about 0.34 mA as we go
through the first quarter-cycle (5ms). If we assume a 4N25, it has a
typical current-transfer ratio of 0.7 at 10mA photodiode current (0.2
min), but that drops by a factor of about 5 once we get down to
0.5mA. So that means that we'll get a maximum of about 50uA of
collector current at the quarter-cycle point when the voltage is at a
maximum. Around the zero-crossing, we won't get enough collector
current in the phototransistor to detect the zero-crossing with any
We could reduce the resistor a bit, but what we really need is to get
at least 1mA of current through the photodiode within about 100us of
the zero-crossing. That means a 10k resistor, which will end up
dissipating about 6W, which I don't consider acceptable.
> I'm not too sure where the microseconds figure is coming from, given that
> you are detecting a on a 50/60Hz signal. In order to have that resolution on
> your switching, you would need a PWM with at least 14 bits of resolution.
> The project is using an 8 bit PWM, which is an order of magnitude less than
> the resolution required for microseconds to be a problem.
Actually I can in principle control the position of the turn-on pulse
with 1us resolution. I should have said "tens of microseconds" rather
than "microseconds", though. I would like to do it in under 100us,
and certainly in under 300us, since that is the point at which there
is enough voltage to turn on the triac reliably.
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