Extracting the linked to file name

[David Clarke]

On Wed, 14 Nov 2001, Rasjid Wilcox wrote:
> 
> filename=`ll symlink.name | sed s/"->"/\|/ | cut -f 2 -d\|`
> 

Just wondering, do you want the full path of the file the link points
to?  If you do this should work:

filename=`ls -la linkname | awk '{print $11}'`

If you just want the actual filename, no path, then this should work:

filename=$(basename `ls -la /bin/mt | awk '{print $11}'`)

Not sure if the above will work for anything except bash.

	Hope this helps.

-- 
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David Clarke <gadicath at yahoo.com> | David Clarke <s3353950>
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